# SAT Math 9.4 Algebra and Functions

SAT Math 9.4 Algebra and Functions

Algebra | Factoring Quadratic Equations Use polynomial identities to solve problem Use polynomial identities to solve problems |

Algebra II | Quadratic Equations |

Algebra and Functions | Solving Quadratic Equations by Factoring |

Language | English Language |

Passport to Advanced Math | Solving quadratic equations |

Product Type | SAT Math |

Quadratic Equations | Quadratic Equations |

SAT | SAT Math |

SAT Math | Algebra and Functions |

### Transcript

This format look familiar to ya?

Well, it really doesn’t look like we can factor this one, so let’s apply the quadratic formula.

So with 3 as a, 5 as b and negative 12, guest starring as c…we can now apply our formula.

Negative 5 plus or minus radical 25 plus negative 4 times 3 times negative 12…equals 144 all over 6.

…and 144 plus 25 is 169…ooh, magic number…

…so we have negative 5 plus or minus 13…all over 6.

Now we can just separate out the two plus or minus options…

…and we have negative 5 plus 13 over 6 and negative 5 minus 13 over 6.

The first one simplifies to 8 over 6, or just 4/3…

…and the second one simplifies to negative 18 over 6, or just negative 3.

So, since the question asks us for the non-integer solution to the equation,

we can forget about that last one.

Later, negative 3. So yeah…the answer is 4/3.